Above is an image of the solution for number 8 of the Common Ion, Precipitate, Concentration Worksheet. Let me point out a couple of key factors: (1) Chromate (CrO4(-2) is not on your solubility sheet. Remember, if you know that all alkali metals and ammonium are soluble and all nitrates are soluble, you can figure out precipitates by deductive reasoning. Thus, the precipitate has to occur between aluminum ion and chromate ion. (2) Hopefully the number of moles of each reactant is easy enough to work with to quickly determine limiting and excess reactants. There will be no limiting reactant left over, so that concentration will always be zero. What is left of the excess reactant will be divided by the total volume to find that concentration. Spectator ion concentrations are simply the mole values of each divided by the total volume. Problems 5 and 7 are very similiar to #8. Come and see me before class if you have any issues with the worksheet.
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