Below is the solution for #55 for tomorrow's homework. The answer for the problem in the book is different than what I determined. Also, #48 is on the previous post. Homework for tomorrow is 46, 48, 53, 54, 55, 56.
Monday, October 26, 2009
Monday, October 26th
Tuesday, October 20, 2009
Tuesday, October 20th
Friday, October 9, 2009
Friday, October 10th
Thursday, October 8, 2009
Thursday, October 8th
Homework for Wednesday, 10/7 - pages 235-237, problems 59, 60, 64, 65, 106
Homework for Thursday, 10/8 - page 236, problems 85 and 86
I would suggest that you read pages 222-224 (Section 5.8) to review the lecture from today on non-ideal behavior of gases. This will be addressed conceptually on the Chapter 5 test, which will be given on Monday, 10/12.
Friday, 10/9, will be spent reviewing for the exam. We will be working on two old AP Chemistry test written problems from 2004.
All solutions to the homework will be posted for the weekend so you can view them as you study.
Homework for Thursday, 10/8 - page 236, problems 85 and 86
I would suggest that you read pages 222-224 (Section 5.8) to review the lecture from today on non-ideal behavior of gases. This will be addressed conceptually on the Chapter 5 test, which will be given on Monday, 10/12.
Friday, 10/9, will be spent reviewing for the exam. We will be working on two old AP Chemistry test written problems from 2004.
All solutions to the homework will be posted for the weekend so you can view them as you study.
Tuesday, October 6, 2009
Tuesday, October 6th
Your Determination of the Molar Mass of Butane Lab is due tomorrow (10/7). You will also have a quiz that covers the concepts of the lab tomorrow (10/7). Below are the answers to the homework assigned on Friday and today.
68) P(H2)=12.2 atm; P(He)=6.2 atm; P(Tot)=18.4 atm
49) 0.268 g He
51) V= 4.23 L
55) 2.47 mol H2O
80) Will be covered in class.
81) 30.00 g/mol; NO gas
82) 63.3 g/mol
68) P(H2)=12.2 atm; P(He)=6.2 atm; P(Tot)=18.4 atm
49) 0.268 g He
51) V= 4.23 L
55) 2.47 mol H2O
80) Will be covered in class.
81) 30.00 g/mol; NO gas
82) 63.3 g/mol
Thursday, October 1, 2009
Thursday, October 1st
Homework for tonight is pages 233-234, problems 36, 37, 38, 40, 41, 45
Answers
36 a) 3.81 x 10^-5 mol
36 b) 179 atm
36 c) 3.6 L
36 d) 333 K or 60. degrees C
37) 4,440 g. He and 2,240 g H2
38) 0.091 atm
40) 0.046 L = 46 mL
41) 3.0 L > 2.5 L, therefore, the balloon will burst.
45) 5.1 x 10^4 torr
Answers
36 a) 3.81 x 10^-5 mol
36 b) 179 atm
36 c) 3.6 L
36 d) 333 K or 60. degrees C
37) 4,440 g. He and 2,240 g H2
38) 0.091 atm
40) 0.046 L = 46 mL
41) 3.0 L > 2.5 L, therefore, the balloon will burst.
45) 5.1 x 10^4 torr
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